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Home/ Questions/Q 6172749
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T23:26:46+00:00 2026-05-23T23:26:46+00:00

$result3=mysql_query(select * from $mail); while($row=mysql_fetch_array($result3)) { if($row[‘status’]!=NULL) { echo $row[‘status’]; echo $row[‘date’]; echo $row[‘time’];

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$result3=mysql_query("select * from $mail"); 

while($row=mysql_fetch_array($result3)) { 
    if($row['status']!=NULL) {   
        echo $row['status'];
        echo $row['date'];
        echo $row['time'];
    }
}

i want that the last field in the database should be displayed first. How to implement this?

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  1. Editorial Team
    Editorial Team
    2026-05-23T23:26:48+00:00Added an answer on May 23, 2026 at 11:26 pm
    $result3 = mysql_query("SELECT * from $mail ORDER BY `date` DESC"); 
    

    Never do yourself what the database can do for you.

    If, for whatever weird reason, you actually want to traverse the result set in reverse order, you’ll have to use mysql_data_seek, starting at mysql_num_rows() - 1 and decrementing the pointer after each call to mysql_fetch_array.

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