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Editorial Team
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Asked: 2026-05-12T10:04:40+00:00

$result=mysql_query(SELECT * FROM playerlocations WHERE player<>’0′); $returntext=; while($row=mysql_fetch_array($result)) { if($returntext!=){$returntext.=&;} $returntext.=$row[‘player’].#.$row[‘locations’]; } the error

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$result=mysql_query("SELECT * FROM playerlocations WHERE player<>'0'");

$returntext="";

while($row=mysql_fetch_array($result))
{
if($returntext!=""){$returntext.="&";}
$returntext.=$row['player']."#".$row['locations'];
}

the error message claims that $result isn’t a valid result set. I tested it in phpmyadmin, and it worked. I don’t know why it won’t work here, please help.

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1 Answer

  1. Editorial Team

    It says it isn’t a valid result set. That doesn’t necessarily mean it isn’t a valid query. (Although != instead of <> would be nice.)

    To figure out why it’s not valid, output the result of calling mysql_error() after running the query:

    echo mysql_error(); //most direct way to do this

    It will tell you what MySQL reports as the error message.

    One obvious thing to check: have you opened the connection (with mysql_connecst()) before running the query?

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