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Asked: 2026-05-20T00:32:26+00:00

results = docDB.posts.find({active:True }).sort(pop_score, pymongo.DESCENDING) This is my sort right now. But the problem

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results = docDB.posts.find({"active":True }).sort("pop_score", pymongo.DESCENDING)

This is my sort right now. But the problem is, some things have the same “score”. In that case, if they tie, I want them to sort by “time” within the ones who tied.

How do I do that? It’s possible to do that in Mysql…

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1 Answer

  1. Editorial Team

    You can sort by more than one attribute at a time. e.g.

    sort({name : 1, age : -1})

    will sort by name ascending then by age descending

    See here for reference: http://www.mongodb.org/display/DOCS/Sorting+and+Natural+Order

    Edit:

    In pymongo, that would be

    .sort([['name', pymongo.ASCENDING], ['age', pymongo.DESCENDING]])

    referenceL http://api.mongodb.org/python/current/api/pymongo/cursor.html#pymongo.cursor.Cursor.sort

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