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Home/ Questions/Q 7797333
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T23:39:06+00:00 2026-06-01T23:39:06+00:00

Right now I have a handful of those in a class: string upgrade_file =

  • 0

Right now I have a handful of those in a class:

string upgrade_file 
    = new StreamReader(Assembly.GetExecutingAssembly().GetManifestResourceStream(
        Assembly.GetExecutingAssembly().GetName().Name 
        + ".schemas.template.db_upgrades.txt")
        ).ReadToEnd();

I can write a wrapper function to simplify accessing embedded resources (and I will if I have to), but is there a simpler or more elegant way to access them natively with .Net?

For example, I find it strange that GetManifestResourceStream(…) isn’t static. Another example: is there some method that returns a string rather than a stream for text files?

UPDATE 1:

To be clear, I have text files in sub-directories, and I want that:

  1. These files remain separate files (for example to be able to source control them separately)
  2. These files remain embedded resources, i.e. compiled with the assembly.

Right now I’m doing this as shown in this image:
enter image description here

UPDATE 2:

I did not manage to use anything from the answers to simplify accessing the files.

Here is the helper method I’m now using in case someone else might find it useful:

/// <summary>
/// Get the content of a text file embedded in the enclosing assembly.
/// </summary>
/// <param name="resource">The "path" to the text file in the format 
/// (e.g. subdir1.subdir2.thefile.txt)</param>
/// <returns>The file content</returns>
static string GetEmbeddedTextFile(string resource)
{
    return new StreamReader(Assembly.GetExecutingAssembly().GetManifestResourceStream(
        Assembly.GetExecutingAssembly().GetName().Name + "." + resource)).ReadToEnd();
}
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  1. Editorial Team
    Editorial Team
    2026-06-01T23:39:07+00:00Added an answer on June 1, 2026 at 11:39 pm

    I have a resource file in my project named Resource1 containing a TXT file and a binary file.
    I’m able to do

    string str = Resource1.TxtFile;
    byte[] file = Resource1.BinaryFile;
    
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