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Home/ Questions/Q 825421
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:15:09+00:00 2026-05-15T03:15:09+00:00

Right now I’m setting the position of a window that is about to open

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Right now I’m setting the position of a window that is about to open like this:

-(void) setActiveNodeDialog:(ISKNodeDialogController *)dialog
{
    if (activeNodeDialog)
        [[activeNodeDialog window] close];
    activeNodeDialog = dialog;
    if (activeNodeDialog) {
        [activeNodeDialog setMainWindowController:self];
        NSRect windowRect = [[self window] frame];
        NSRect dialogRect = [[activeNodeDialog window] frame];
        NSPoint pos;
        pos.x = windowRect.origin.x + windowRect.size.width - dialogRect.size.width - 10;
        pos.y = windowRect.origin.y + 32;
        [[activeNodeDialog window] setFrameOrigin:pos];
        [[activeNodeDialog window] makeKeyAndOrderFront:nil];
    }
}

The problem with that is, that the window will “jump” when shown. And that even though I set the position before showing the window with “makeKeyAndOrderFront”. The window is a NSPanel *. Anyone any ideas how to fix the jumping?

Setting the position in awakeFromNib is not an option because the main controller is set later.

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  1. Editorial Team
    Editorial Team
    2026-05-15T03:15:10+00:00Added an answer on May 15, 2026 at 3:15 am

    In Interface Builder, is “visible at launch” checked for the window? If so uncheck it and then you won’t even need this code [[activeNodeDialog window] close];. Basically if that is checked then the window is automatically shown when the xib is instantiated… which you don’t want.

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