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Home/ Questions/Q 7741323
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T08:59:50+00:00 2026-06-01T08:59:50+00:00

R’s data.table package offers fast subsetting of values based on keys. So, for example:

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R’s data.table package offers fast subsetting of values based on keys.

So, for example:

set.seed(1342)

df1 <- data.table(group = gl(10, 10, labels = letters[1:10]),
                  value = sample(1:100))
setkey(df1, group)

df1["a"]

will return all rows in df1 where group == “a”.

What if I want all rows in df1 where group != "a". Is there a concise syntax for that using data.table?

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  1. Editorial Team
    Editorial Team
    2026-06-01T08:59:51+00:00Added an answer on June 1, 2026 at 8:59 am

    I think you answered your own question:

    > nrow(df1[group != "a"])
    [1] 90
    > table(df1[group != "a", group])
    
     a  b  c  d  e  f  g  h  i  j 
     0 10 10 10 10 10 10 10 10 10 
    

    Seems pretty concise to me?

    EDIT FROM MATTHEW : As per comments this a vector scan. There is a not join idiom here and here, and feature request #1384 to make it easier.

    EDIT: feature request #1384 is implemented in data.table 1.8.3

    df1[!'a']
    
    # and to avoid the character-to-factor coercion warning in this example (where
    # the key column happens to be a factor) :
    df1[!J(factor('a'))]
    
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