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Ruby 1.8.7:
"abc"[0]
=> 65
Ruby 1.9*
"abc"[0]
=> "a"
Is there a way I can safely write the code above to produce the second result in both 1.8.7 and 1.9*? My solution so far is: "abc".split('').first but that doesn’t seem very clever.
produces the 2nd result in both versions.
1.8: http://ruby-doc.org/core-1.8.7/Integer.html#method-i-chr
1.9: http://ruby-doc.org/core-1.9.3/String.html#method-i-chr