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Home/ Questions/Q 4087540
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T18:52:05+00:00 2026-05-20T18:52:05+00:00

ruby-1.9.2-p180 :154 > a = [] => [] ruby-1.9.2-p180 :154 > h = {:test

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ruby-1.9.2-p180 :154 > a = []
 => []
ruby-1.9.2-p180 :154 > h = {:test => "test"}
 => {:test=>"test"} 
ruby-1.9.2-p180 :155 > a << h
 => [{:test=>"test"}] 
ruby-1.9.2-p180 :156 > h.clear
 => {} 
ruby-1.9.2-p180 :157 > a
 => [{}] 

I’m very confused, especially since I can change the elements of the hash without it affecting the array. But when I clear the hash the array is updated and cleared of its hash contents. Can someone explain?

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  1. Editorial Team
    Editorial Team
    2026-05-20T18:52:05+00:00Added an answer on May 20, 2026 at 6:52 pm

    When you do a << h, you are really passing the reference of h to a. So when you update h, a also see’s those changes because it contains a reference rather than a copy of that value.

    In order for it not to change in a, you must pass a cloned value of h into a.

    An example would be:

    a << h.clone
    
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