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Home/ Questions/Q 374901
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T14:27:02+00:00 2026-05-12T14:27:02+00:00

ruby has some edge cases which is hard to explain because parsing brings some

  • 0

ruby has some edge cases which is hard to explain because parsing brings some interesting issues. Here I am listing two of them. If you know of more then add to the list.

def foo
  5
end

# this one works
if (tmp = foo)
  puts tmp.to_s
end

# However if you attempt to squeeze the above
# three lines into one line then code will fail
# take a look at this one. I am naming tmp2 to 
# avoid any side effect

# Error: undefined local variable or method ‘tmp2’ for main:Object
puts tmp2.to_s if (tmp2 = foo)

Here is another one.

def x
  4
end

def y
  x = 1 if false 
  x + 2
end

# Error: undefined method `+' for nil:NilClass
puts y

However if you comment out the line x = 1 if false then code will work fine.

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  1. Editorial Team
    Editorial Team
    2026-05-12T14:27:02+00:00Added an answer on May 12, 2026 at 2:27 pm

    In your first example tmp2 is not assigned until it reaches the if statement.

    Your second example is not unexpected. Even though x is never assigned it informs the interpreter that you are talking about variable x not function x in the next line. Ruby tries to be pretty loose when determining the context of a name but it will take clues where available. It helps to be specific, for instance:

    def y
      x = 1 if false
      x() + 2
    end
    
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