Question

s = Proc.new {|x|x*2}
puts "proc:" + (s.call(5)).to_s

def foo(&a)
    a.call(5)
end
foo{|x| puts "foo:" + (x*3).to_s}

Running this program produces the output:

proc:10
foo:15

How does the value 3 from the foo block get passed to the proc? I expected this output:

proc:10
foo:10

The proc is always called with the value 5 as the argument because foo is defined as:

    a.call(5)

Why is foo 15 in the output?

Answer 1

The value 3 does not get passed to the proc because you’re not passing s to foo. You probably meant to write

foo {|x| puts "foo: #{s.call(x)}"}

or

puts "foo: #{foo(&s)}"

Additionally, these are equivalent:

def foo_1(x, &a)
  puts a.call(x)
end
def foo_2(x)
  puts yield(x)
end

foo_1(5, &s) #=> 10
foo_2(5, &s) #=> 10