Question

Sample Input : “car truck 8 4 bus 6 1”

Sample Output : “bus car 1 4 truck 6 8”

If the nth element in the string is an integer it must remain an integer,
and if it is a word it must remain a word

Is there a more elegant and efficient way of doing this? Below is my ruby code. I am looking for code which is more efficient(need not be in ruby).

puts "Enter Input:"
inp = gets

inp_ary=inp.split(" ")

a=inp_ary.group_by{|i| i=~ /\d/}

sort_words = a[nil].sort
sort_integer = a[0].sort

index_words=[]
index_integer=[]

inp_ary.each_with_index do |e,i|
  if e =~ /\d/
    index_integer << i
  else
    index_words << i
  end
end

final = []

sorted = sort_words + sort_integer

index_integer.each_with_index do |e,i|
  final[e] = sort_integer[i]
end

index_words.each_with_index do |e,i|
  final[e] = sort_words[i]
end

puts "Sorted Output: "
puts final.join(" ")

Answer 1

s = "car truck 8 4 bus 6 1"

tokens = s.split
numbers, words = tokens.partition{|t| t =~ /^\d+$/}
numbers.map!(&:to_i).sort!
words.sort!

result = tokens.map{|t| (t =~ /^\d+$/ ? numbers : words).shift}.join(' ')

p result
#=> "bus car 1 4 truck 6 8"