Question

Sample table ID: (num is a key so there wouldn’t be any duplicates)

num
1
5
6
8
2
3

Desired output:
(Should be sorted and have a cumulative sum column)

num cumulative
1    1
2    3
3    6
5    11
6    17
8    25

This is one solution I got:

select a.num, sum(b.num) from ID a, ID b where b.num <= a.num group by a.num order by a.num;

Answer 1

I think I figured out the solution.

Select num as n, 
       (select sum(num) from ID where num <= n)
from ID order by n;