Question

Say for example this is my code:

$query = "SELECT * FROM ...";
$exec_query = mysql_query($query, $db_connect);
$fetchdetails = mysql_fetch_array($exec_query);

I am using an if condition like this:

if ($fetchdetails['field_name'] == 3) {
 do something;
}

else {
}

But in this, only 1 row is compared from the fetchdetails array. What can I do to compare each row in that array with 3? I don’t want any OOP’s solutions, please, I want to stick with traditional coding. Thank you.

Answer 1

You should try this:

while($fetchdetails = mysql_fetch_array($exec_query)) {
 if ($fetchdetails['field_name'] == 3) {
  do something;
 }

 else {
 }

}

That’s because, with the while(...) condition, you’ll iterate over all db (selected) records.
The loop will stop in an automatic way as soon as mysql_fetch_array finish record.

I’ll remember you that mysql_fetch_array

Returns an array of strings that corresponds to the fetched row, or FALSE if there are no more rows. (from manual)

and that will allow “you” to stop iteration process.