Say I have 2 HTML pages, foo.html and bar.html.
Inside foo.html:
<a href="/foo.html" class="selected">Open Foo</a>
<a href="/bar.html">Open Bar</a>
<!-- shared content -->
<div id="content">Nested HTML specific to Foo</div>
<!-- shared content -->
Inside bar.html:
<a href="/foo.html">Open Foo</a>
<a href="/bar.html" class="selected">Open Bar</a>
<!-- shared content -->
<div id="content">Nested HTML specific to Bar</div>
<!-- shared content -->
As expected, when I click a link in either page, it will open the corresponding page. Now, I want to “AngularJSify” this so that clicking a link will only update div#content. I tried this:
$routeProvider
.when('/foo.html', {templateUrl:'/foo.html?onlyContent=true'})
.when('/bar.html', {templateUrl:'/bar.html?onlyContent=true'})
<div id="content" ng-view>Nested HTML specific to Foo (or Bar, depending which page you're in)</div>
But opening foo.html will also load foo.html?onlyContent=true which is unnecessary because foo.html already has the content!
You might be asking, “Why not use empty div#content?” Because I want to (1) Reduce loading extra file, and (2) Make the content available even if JS is disabled.
In Backbone.js I can use:
Backbone.history.start({pushState:true, silent:true});
Which basically means, “If the page is already loaded, don’t invoke the route again.” How do I achieve that in AngularJS?
Inside
foo.html:Inside
bar.html:In JavaScript:
Essentially means, “if the route you’re opening is the same with the path in address bar, use template from current page instead”.