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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T20:30:13+00:00 2026-05-18T20:30:13+00:00

Say I have a byte like this 1010XXXX where the X values could be

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Say I have a byte like this 1010XXXX where the X values could be anything. I want to set the lower four bits to a specific pattern, say 1100, while leaving the upper four bits unaffected. How would I do this the fastest in C?

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  1. Editorial Team
    Editorial Team
    2026-05-18T20:30:13+00:00Added an answer on May 18, 2026 at 8:30 pm

    You can set all those bits to 0 by bitwise-anding with the 4 bits set to 0 and all other set to 1 (This is the complement of the 4 bits set to 1). You can then bitwise-or in the bits as you would normally.

    ie

     val &= ~0xf; // Clear lower 4 bits. Note: ~0xf == 0xfffffff0
     val |= lower4Bits & 0xf; // Worth anding with the 4 bits set to 1 to make sure no
                              // other bits are set.
    
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