Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4250326
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 21, 20262026-05-21T04:30:50+00:00 2026-05-21T04:30:50+00:00

Say I have a class Mother with a oneToMany mapping to Kittens @Entity @org.hibernate.annotations.Entity(dynamicUpdate

  • 0

Say I have a class Mother with a oneToMany mapping to Kittens

@Entity
@org.hibernate.annotations.Entity(dynamicUpdate = true)
@Table(name = "Mother")

.....

@OneToMany(fetch = FetchType.LAZY, targetEntity=Kittens.class, cascade=CascadeType.ALL)
@JoinColumn(name="motherId")
private List<Kittens> kittens;

I am using the criteria Api to provide a list

Criteria criteria = this.getSession().createCriteria(Mother.class);
Criterion MotherType = Restrictions.eq("type", "domesticated");
criteria.add(MotherType)
.addOrder(Order.asc("motherName"))
.setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY)
.setFetchMode("kittens", FetchMode.JOIN)
// .addOrder(Order.asc("kittens.kittenName"));
List test = criteria.list();

Works fine until I try to add the order of the kittens field kittenName

I’ve also tried adding the @OrderBy(value=”kittenName”) annotation under the Kitten @OneToMany(…etc ) which works fine until you use the criteria API and this order will precede any other order statements in the sql.

Cheers in advance for any help…

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-21T04:30:51+00:00Added an answer on May 21, 2026 at 4:30 am

    You need to add the @javax.persistence.OrderBy annotation to your kittens list.

    @OneToMany(fetch = FetchType.LAZY,
               targetEntity=Kittens.class,
               cascade=CascadeType.ALL)
    @JoinColumn(name="motherId")
    @OrderBy("kittenName")
    private List<Kittens> kittens;
    

    @See

    • Hibernate Annotations Reference Guide
    • Chapter 2.2.5. Mapping entity associations/relationships
    • Subchapter 2.2.5.3.4. Indexed collections (List, Map)
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Say I have a class with a private dispatch table. $this->dispatch = array( 1
Say I have a class, User: public class User { private String name; private
let say we have class Person($name), Does $name need to be asigned as null
Lets say I have class Person { public Person(int age, string name) { Age
Let's say I have class objectA { string name; } class objectB { List<objectA>
Say I have public class family { public person father; public person mother; public
Say I have class A with class A { final String foo() { //
Say we have: class Base { virtual void f() {g();}; virtual void g(){//Do some
Say I have: class Vector3 { float x, y, z; ... bunch of cuntions
say I have: class Test { public static int Hello = 5; } This

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.