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Home/ Questions/Q 6604837
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:12:36+00:00 2026-05-25T19:12:36+00:00

Say I have a custom type in my set, and the set/ordering only makes

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Say I have a custom type in my set, and the set/ordering only makes sense if all items have the same value on some property… if an item with a different value is inserted the model is screwed up and I want to protect this.

I thought maybe the comparison function might be a place we could test this (as an assert or exception) to either flag the problem and/or prevent the item getting inserted. e.g on TypeName, operator<() always returns false if the important attribute isn’t equal.

Is this reasonable?

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:12:37+00:00Added an answer on May 25, 2026 at 7:12 pm

    I guess putting it in the comparator could have issues as you’ve not got any guarantees when it’s going to be called. Perhaps some mythical implementation stores items in a list when the number of items is small and doesn’t call the comparator until later?

    Probably the simplest approach would be to wrap the std::set in a protective outer class that performed these assertions.

    class MySet {
      private:
         std::set<myFunkyType> myType;
    
      public:
         void insert(myFunkyType type) {
            assert(!type.isFunky(), "funk violation");
            // and so on
         }
    
         // all other members other than insertion or mutation just delegate to the
         // underlying set
    

    }

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