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Home/ Questions/Q 718145
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:29:36+00:00 2026-05-14T05:29:36+00:00

Say I have a function foo: (defun foo (x y &rest args) …) And

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Say I have a function foo:

(defun foo (x y &rest args)
...)

And I later want to wrap it with a function bar:

(defun bar (x &rest args)
(foo x 100 args))

Assume bar was then called like this: (bar 50 1 2 3)

With this setup, args is a list within the body of bar that holds the trailing parameters, so when I pass it to foo, instead of getting the equivalent of (foo 50 100 1 2 3) I of course get (foo 50 100 '(1 2 3)). If these were macros, I would use “(foo ,x 100 ,@args)` within the body of bar to splice args into the function call. ,@ only works inside a backtick-quoted list, however.

How can I do this same sort of splicing within a regular function?

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:29:36+00:00Added an answer on May 14, 2026 at 5:29 am

    APPLY will call its first argument with its subsequent arguments, and the last argument must be a list. So:

    (apply #'foo x 100 args)
    
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