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Home/ Questions/Q 8521555
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T06:51:42+00:00 2026-06-11T06:51:42+00:00

Say I have a function that returns a quoted list like so: (defun create-structure

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Say I have a function that returns a quoted list like so:

(defun create-structure (n l)
  '(structure (name . n)(label . l)))

I’d like the function to return:

(create-structure foo bar)
-> '(structure (name . foo)(label . bar))

Instead I get as excpected:

-> '(structure (name . n)(label . l))
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  1. Editorial Team
    Editorial Team
    2026-06-11T06:51:43+00:00Added an answer on June 11, 2026 at 6:51 am

    There are at least two ways to achieve this, Using the backquote syntax or an explicit call to list.

    (defun create-structure-1 (n l)
      `(structure (name . ,n) (label . ,l)))
    
    (defun create-structure-2 (n l)
      (list 'structure (cons 'name n) (cons 'label l)))
    

    The GNU Emacs Lisp Reference provides a good read on the subject:
    – http://www.gnu.org/software/emacs/manual/html_node/elisp/Backquote.html#Backquote

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