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Home/ Questions/Q 301731
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T07:01:58+00:00 2026-05-12T07:01:58+00:00

Say I have a jQuery plugin like $.abc = function() {}. Now I want

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Say I have a jQuery plugin like $.abc = function() {}. Now I want to provide an extra module which uses the same scope as $.abc and extends its functionality. For e.g. in my abc plugin I will check if say a variable mod1 = true; if its true, then I will automatically call thoso functions of mod1.

My question is how do I write mod1 so that it can share the same namespace as my base plugin and I am able to call it from my plugin e.g. mod1.getFiles();

Thankyou for your time. Sorry if this is not very clear. I will explain again if you have any questions.

UPDATE: How do I call function test of pluginbar?

$.fn.pluginFoo = function() {
    ...
     CALL FUNCTION TEST OF PLUGINBAR
    ...
};

$.fn.pluginBar = function() {
    ...
    function test() {
        alert('this is a test'); 
    }
    ...
};
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  1. Editorial Team
    Editorial Team
    2026-05-12T07:01:58+00:00Added an answer on May 12, 2026 at 7:01 am

    There is no need to create a shared data object. You can expose some functionality of one plugin to other plugins using simply return statement.

    $.fn.pluginFoo = function () {
         // here you can access public "members" of pluginBar
         $.fn.pluginBar.fn3();
         $.fn.pluginBar.fn4();
    }
    
    
    $.fn.pluginBar = function () {
        // private "members" (only this plugin can access them)
        var fn1 = function () { ... }
        var fn2 = function () { ... }
    
        // public "members" (other plugin can access that as well)
        // fn3 is defined in the return, fn4 allows to access private function fn1
        return {
            fn3: function () { ... },
            fn4: fn1
        };
    }
    
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