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Home/ Questions/Q 4041946
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T12:56:39+00:00 2026-05-20T12:56:39+00:00

Say I have a list with keywords: ‘((element1 :keyword1 a :keyword2 b) (element2 :keyword3

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Say I have a list with keywords:

'(("element1" :keyword1 "a" :keyword2 "b") 
  ("element2" :keyword3 "c" :keyword4 "d")
  ("element3" :keyword2 "e" :keyword4 "f"))

Which functions can I use to find which list elements contain :keyword2 and find its value in each list? I’m trying to do this in Emacs Lisp but I think with the cl package I could possibly adapt a Common Lisp solution? I’ve tried to use the find function as illustrated here but to no avail (of course, after changing a few syntax elements to adapt the examples to Emacs Lisp).

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  1. Editorial Team
    Editorial Team
    2026-05-20T12:56:39+00:00Added an answer on May 20, 2026 at 12:56 pm
    (require 'cl)
    
    (defvar *data* '(("element1" :keyword1 "a" :keyword2 "b") 
                     ("element2" :keyword3 "c" :keyword4 "d")
                     ("element3" :keyword2 "e" :keyword4 "f")))
    
    (find :keyword2 *data* :test #'find)
    ;;=> ("element1" :keyword1 "a" :keyword2 "b")
    
    (getf (cdr (find :keyword2 *data* :test #'find)) :keyword2)
    ;;=> "b"
    
    ;; Above only finds the first match; to find all matches, 
    ;; use REMOVE* to remove elements that do not contain the keyword:
    
    (remove* :keyword2 *data* :test-not #'find)
    ;;=> (("element1" :keyword1 "a" :keyword2 "b")
    ;;    ("element3" :keyword2 "e" :keyword4 "f"))
    
    (mapcar (lambda (x) (getf (cdr x) :keyword2))
            (remove* :keyword2 *data* :test-not #'find))
    ;;=> ("b" "e")
    
    
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