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Home/ Questions/Q 6709897
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:56:11+00:00 2026-05-26T07:56:11+00:00

Say I have a member function that creates a new object and places it

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Say I have a member function that creates a new object and places it into a data structure (in this case a map) in the class:

Class A
{
    std::map<std::pair<int,int>, BaseClass*> store;
    //...
    public:
    void createObject(?a?)
    {
        BaseClass* temp = new ?a?;
        //place in map...
    };
};

Where ?a? is an argument that can be used to create an object that can be a number of different classes derived from BaseClass. The only way I can think of doing this is by making ?a? an int, and manually typing each type into a switch statement.

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:56:11+00:00Added an answer on May 26, 2026 at 7:56 am

    Use a member function template. In the context of your example:

    template<class T>
    void createObject()
    {
        BaseClass* temp = new T();
        //place in map...
    };
    

    Invoke with:

    a.createObject<B>();
    

    Where a is an instance of A, and B is a type derived from BaseClass.

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