Question

Say i have a object in dynamic memory (new) and inside one of its functions, it has

int Obj1::Add(int a, int b)
{
    int c = a + b;
    return c;
}

Is c (and a and b…) on the stack ? or in dynamic memory with my object. Just curious 🙂 Thanks

Answer 1

All of those will be on the stack. a and b are passed parameters so, even if the originals were in the heap, a copy would be made on the stack. If you were passing by reference, it may be a different matter since the thing actually sent across (“under the hood”) would be more of a pointer to the original.

For c, since it’s a local variable, it’s on the stack too.

That’s of course assuming your implementation even uses a stack, and that optimisation hasn’t just stashed them into registers. It’s really totally up to the implementation.