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Home/ Questions/Q 6668331
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:01:47+00:00 2026-05-26T03:01:47+00:00

Say I have a query such as: SELECT * FROM Table_1 JOIN Table_2 ON

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Say I have a query such as:

SELECT *
FROM Table_1
JOIN Table_2
ON Table_1.Col_1 = Table_2.Col_1

So I have 100 records and 98 of them are equal so that query would print out 98 out of 100. How can I get SQL to print the 2 that failed to meet the join?

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:01:48+00:00Added an answer on May 26, 2026 at 3:01 am

    Use a LEFT JOIN:

    SELECT *
    FROM Table_1
    LEFT JOIN Table_2 ON (Table_1.Col_1 = Table_2.Col_1)
    

    The fields of Table_2 will be NULL where there was no match for the ON clause. You’ll then be able to add a WHERE TABLE_2.Col_1 IS NULL to keep only records in Table_1 that didn’t have a match in Table_2.

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