Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 824825
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T03:09:23+00:00 2026-05-15T03:09:23+00:00

Say I have a struct that looks like this (a POD): struct Foo {

  • 0

Say I have a struct that looks like this (a POD):

struct Foo
{
  int i;
  double d;
};

What are the differences between the following two lines:

Foo* f1 = new Foo;
Foo* f2 = new Foo();
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T03:09:24+00:00Added an answer on May 15, 2026 at 3:09 am

    The first one leaves the values uninitialised; the second initialises them to zero. This is only the case for POD types, which have no constructors.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Say i have a data structure like this: type Foo struct { Bar []struct
Say I have some windows method and a struct: struct SomeStruct{ int foo; int
Let's say I have the following method: public static int CountNonNullMembers<T>(this IEnumerable<T> enumerable) {
Say I have a struct s with an int pointer member variable i. I
Say we have the following method: private MyObject foo = new MyObject(); // and
Say I have a class named Frog, it looks like: public class Frog {
Suppose I have a C++ struct that has both POD and non-POD member variables:
Say I have the following C++: char *p = new char[cb]; SOME_STRUCT *pSS =
Let's say have something like: SELECT energy_produced, energy_consumed, timestamp1 AS timestamp FROM ( SELECT
Say I have the following file structure: app/ app.py controllers/ __init__.py project.py plugin.py If

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.