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Home/ Questions/Q 7508195
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T22:38:16+00:00 2026-05-29T22:38:16+00:00

Say I have a templated class like template <typename T> struct Node { //

  • 0

Say I have a templated class like

template <typename T> struct Node
{
    // general method split
    void split()
    {
        // ... actual code here (not empty)
    }
};

Need to specialise this in the Triangle class case.. something like

template <>
struct Node <Triangle*>
{
    // specialise the split method
    void split() {}
} ;

but I don’t want to rewrite the entire template over again! The only thing that needs to change is the split() method, nothing more.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T22:38:16+00:00Added an answer on May 29, 2026 at 10:38 pm

    You can provide a specialization for only that function outside the class declaration.

    template <typename T> struct Node
    {
        // general method split
        void split()
        {
            // implementation here or somewhere else in header
        }
    };
    

    // prototype of function declared in cpp
    void splitIntNode( Node & node );

    template <>
    void Node<int>::split()
    {
         splitIntNode( this ); // which can be implemented
    }
    
    int main(int argc, char* argv[])
    {
       Node <char> x;
       x.split(); //will call original method
       Node <int> k;
       k.split(); //will call the method for the int version
    }
    

    If splitIntNode needs access to private members, you can just pass those members into the function rather than the whole Node.

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