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Home/ Questions/Q 6128663
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:39:08+00:00 2026-05-23T16:39:08+00:00

Say I have an array of chars, which I have allocated on the heap,

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Say I have an array of chars, which I have allocated on the heap, and which I want to convert into an std::string. Currently I am doing the following:

char *array = new char[size];
WriteIntoArray(array, size);
std::string mystring(array);
delete[] array;
return mystring; // or whatever

From what I read on the internet (http://www.cplusplus.com/reference/string/string/string/), the string constructor performs a copy of the buffer I pass it, leaving me to free the buffer (later, the string frees its internal buffer). What I would like to do is to allocate my buffer, transfer control of it to the string, and then have it free my buffer when it is destructed.

The question initializing std::string from char* without copy looked promising, but my code relies on API calls (“WriteIntoArray” in the above example) which have to write into an array of chars, so I have to create a C-style char* buffer, and cannot convert my code to use only built-in string operations (which was the answer suggested).

Is there some standard way to do this, or should I just write my own string class (ugh)? Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:39:09+00:00Added an answer on May 23, 2026 at 4:39 pm

    If you’re using a conforming C++0x implementation, or one of the many C++ libraries that guarantee contiguous storage for std::string, then you can get a char* that points directly to the storage used by your std::string.

    For example:

    std::string mystring;
    mystring.resize(size);
    WriteIntoArray(&mystring[0], size);
    return mystring;
    

    You may have to think carefully about a null terminator, however.

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