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Asked: 2026-05-11T11:23:24+00:00

Say I have classes Foo and Bar set up like this: class Foo {

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Say I have classes Foo and Bar set up like this:

class Foo { public:     int x;      virtual void printStuff()     {         std::cout << x << std::endl;     } };  class Bar : public Foo { public:     int y;      void printStuff()     {         // I would like to call Foo.printStuff() here...         std::cout << y << std::endl;     } };

As annotated in the code, I’d like to be able to call the base class’s function that I’m overriding. In Java there’s the super.funcname() syntax. Is this possible in C++?

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1 Answer

  1. In C++ you have to explicitly name the base class in calling the derived class method. This can be done from any method from the derived class. The override is a special case of the method of the same name. In Java there is no multi inheritance, so you can use super which will uniquely name the base class. The C++ syntax is like this:

    class Bar : public Foo {   // ...    void printStuff() override {  // help the compiler to check     Foo::printStuff(); // calls base class' function   } };
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