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Home/ Questions/Q 8023507
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T22:34:58+00:00 2026-06-04T22:34:58+00:00

Say I have multiple list items in a <ul> , and there are groups

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Say I have multiple list items in a <ul>, and there are groups of items than contain the .aggregated class. Like this:

<ul>
    <li></li>
    <li></li>
    <li></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
    <li></li>
    <li></li>
    <li></li>
    <li class="aggregated"></li>
    <li class="aggregated"></li>
</ul>

I need to be able to style each of those groups of <li> elements differently, basically giving each group a different background color. So, the first group of <li class="aggregated"> would have a blue background, and the second group a yellow background, etc. I don’t want to rely on JS and don’t want to add arbitrary class names or IDs. I’d like to use the code that’s already in place.

Possible? If so, how?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T22:34:59+00:00Added an answer on June 4, 2026 at 10:34 pm

    Okay, this is possible. But it’s insanely fragile, and relies on there being predictable classes, also it requires a modern browser:

    /* presentational stuff */
    
    li ~ li.aggregated,
    li.aggregated ~ li.aggregated {
        background-color: #f90;
    }
    
    li.aggregated ~ li:not(.aggregated) ~ li.aggregated {
        background-color: #ffa;
    }
    
    li.aggregated ~ li:not(.aggregated) ~ li.aggregated ~ li:not(.aggregated) ~ li.aggregated {
        background-color: #cfc;
    }​
    

    JS Fiddle demo.

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