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Home/ Questions/Q 8566823
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T17:44:40+00:00 2026-06-11T17:44:40+00:00

Say I have some code: def foo(s:String):Either[Bar, Baz] = // some code here …

  • 0

Say I have some code:

def foo(s:String):Either[Bar, Baz] = // some code here ... 

I want to use it as:

val a = Array("a", "b", "c")
a.map(foo) match {
   case something => // should match when all elements in array are of type Right
   case _ =>
}

Can anyone suggest code for “something”

EDIT: Prefer to match and use array of Right[Bar,Baz] directly rather than having to extract after match.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T17:44:41+00:00Added an answer on June 11, 2026 at 5:44 pm

    Use the forall method to check that all elements in the array are isRight:

    a.map(foo) match {
      case eithers if eithers.forall(_.isRight) =>
      case _ =>
    }
    

    Regarding your comment, if you want the match and convert-to-right all in one pass, then try a custom extractor:

    object RightArrayExtractor {
      def unapply(eithers: Array[Either[Bar, Baz]]) =
        eithers.foldLeft(Option(Vector[Right[Bar, Baz]]())) {
          case (Some(z), x @ Right(_)) => Some(z :+ x)
          case (None, _) => None
          case (_, Left(x)) => None
        }
    }
    
    a.map(foo) match {
      case RightArrayExtractor(eithers) => // eithers is a Vector[Right[Bar,Baz]]
      case _ =>
    }
    
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