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Home/ Questions/Q 7502091
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T20:45:00+00:00 2026-05-29T20:45:00+00:00

Say I have the following JSON string returned from server: { response:{ imageInstances:{ one:{

  • 0

Say I have the following JSON string returned from server:

{
    "response":{
        "imageInstances":{
            "one":{
                "id":"1",
                "url":"ONE"
            },         
            "two":{
                "id":"2",
                "url":"TWO"
            }
        }
    }  
}

in codehaus Jackson @JsonProperty, how can I get a HashMap object out of it?

import org.codehaus.jackson.annotate.JsonAnySetter;
import org.codehaus.jackson.annotate.JsonProperty;

import java.util.HashMap;
import java.util.List;

public class MSShow {
  @JsonProperty("imageInstances") private HashMap<String, Temp> images;//// HOW DO YOU CONVERT IT TO HASH MAP??????
  @JsonAnySetter public void ignoredField(String key, Object value) { }

  private class Temp {
    @JsonProperty("id") private String id;
    @JsonProperty("url") private String url;
    @JsonAnySetter public void ignoredField(String key, Object value) { }
    }
}

At the end of the day, I want the hash map generated based on the returned JSON string to be
(written in java pseudo)

should return me a Temp object with fields id=1 and url=ONE if I call

images.get("one")

should return me a Temp object with fields id=2 and url=TWO if I call

images.get("two") 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T20:45:02+00:00Added an answer on May 29, 2026 at 8:45 pm

    That should work as is, with one small modification: you are using extra “response” entry. So typically you would either use a wrapper POJO like:

    class Wrapper {
      public MSShow response;
    }
    

    to map structure properly. Or you can use UNWRAP_ROOT_VALUE Feature (from DeserializationConfig) to do this automatically, although name of the class needs to match if so.

    Result will indeed be a HashMap if the field type is that (which it is). If it wasn’t you could also use:

    @JsonDeserialize(as=HashMap.class)
    

    to force specific subtype to be used.

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