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Home/ Questions/Q 43867
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Asked: May 10, 20262026-05-10T15:33:46+00:00 2026-05-10T15:33:46+00:00

Say I have the following methods: def methodA(arg, **kwargs): pass def methodB(arg, *args, **kwargs):

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Say I have the following methods:

def methodA(arg, **kwargs):     pass  def methodB(arg, *args, **kwargs):     pass 

In methodA I wish to call methodB, passing on the kwargs. However, it seems that if I define methodA as follows, the second argument will be passed on as positional rather than named variable arguments.

def methodA(arg, **kwargs):     methodB('argvalue', kwargs) 

How do I make sure that the **kwargs in methodA gets passed as **kwargs to methodB?

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  1. 2026-05-10T15:33:46+00:00Added an answer on May 10, 2026 at 3:33 pm

    Put the asterisks before the kwargs variable. This makes Python pass the variable (which is assumed to be a dictionary) as keyword arguments.

    methodB('argvalue', **kwargs) 
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