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Home/ Questions/Q 9135767
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T08:51:58+00:00 2026-06-17T08:51:58+00:00

Say I have the following struct: typedef struct elementT { int value; struct element

  • 0

Say I have the following struct:

typedef struct elementT {
  int value;
  struct element *next;
} element;

What would be the difference between doing:

element *newElem;
newElem = malloc(sizeof(element))

And doing this:

element *newElem;
newElem = (element *) malloc(sizeof(element))

From my point of view, in the first case we are doing:

element *newElem; -> Create a pointer for an address that contians an element type.
newElem = malloc(sizeof(element)) -> Make that pointer to point to the result of the malloc.

Why do we need to do (element *), or why is it useful?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T08:51:59+00:00Added an answer on June 17, 2026 at 8:51 am

    It’s from old style C where void * wasn’t really allowed so everything returned char *, this would cause the compiler to generate a warning saying that you were assigning incompatible pointer types and casting was simply a way to get rid of this warning. Newer compilers know what you are trying to do and make the cast unnecessary (except in certain situations such as the Linux kernel vmalloc function).

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