Home/ Questions/Q 4266890
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-21T06:49:23+00:00

Say I have this single string, here I denote spaces ( ) with ^

  • 0

Say I have this single string, here I denote spaces (” “) with ^

^^quick^^^\n
^brown^^^\n
^^fox^^^^^\n

What regular expression to use to remove trailing spaces with .replace()?
using replace(/\s+$/g, "") not really helpful since that only removes the spaces
on the last line with “fox”.

Going through other questions I found that replace(/\s+(?:$|\n)/g,"") matches the right sections
but also gets rid of the new line characters but I do need them.

So the perfect result will be:

^^quick\n
^brown\n
^^fox\n

(only trailing spaces are removed everything else stays)

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Add the 'm' multi-line modifier.

    replace(/\s+$/gm, "")

    Or faster still…

    replace(/\s\s*$/gm, "")

    Why is this faster? See: Faster JavaScript Trim

    Addendum: The above expression has the potentially unwanted effect of compressing adjacent newlines. If this is not the desired behavior then the following pattern is preferred:

    replace(/[^\S\r\n]+$/gm, "")

    Edited 2013-11-17: – Added alternative pattern which does not compress consecutive newlines. (Thanks to dalgard for pointing this deficiency out.)

    • 0