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Home/ Questions/Q 790063
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T21:37:30+00:00 2026-05-14T21:37:30+00:00

Say, I have three interfaces: public interface I1 { void XYZ(); } public interface

  • 0

Say, I have three interfaces:

public interface I1
{
    void XYZ();
}
public interface I2
{
    void XYZ();
}
public interface I3
{
    void XYZ();
}

A class inheriting from these three interfaces:

class ABC: I1,I2, I3
{
      // method definitions
}

Questions:

  • If I implement like this:

    class ABC: I1,I2, I3
    {

        public void XYZ()
        {
            MessageBox.Show("WOW");
        }
    

    }

It compiles well and runs well too!
Does it mean this single method implementation is sufficient for inheriting all the three Interfaces?

  • How can I implement the method of all the three interfaces and CALL THEM?
    Something Like this:

    ABC abc = new ABC();
    abc.XYZ(); // for I1 ?
    abc.XYZ(); // for I2 ?
    abc.XYZ(); // for I3 ?
    

I know it can done using explicit implementation but I’m not able to call them. 🙁

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T21:37:31+00:00Added an answer on May 14, 2026 at 9:37 pm

    If you use explicit implementation, then you have to cast the object to the interface whose method you want to call:

    class ABC: I1,I2, I3
    {
        void I1.XYZ() { /* .... */ }
        void I2.XYZ() { /* .... */ }
        void I3.XYZ() { /* .... */ }
    }
    
    ABC abc = new ABC();
    ((I1) abc).XYZ(); // calls the I1 version
    ((I2) abc).XYZ(); // calls the I2 version
    
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