Question

Say I’ve a Python list as below:

list =  [ ['text',2,3,4], ['text2',4,5,6] ]
y= map(sum,zip(*list))
print y 

Gives int /str error.

How would I pop all ‘text’ in all rows and sum the remaining columns.
Ans: Im looking for [6, 8, 10]
I noticed that field look like int but are str. 4 vs ‘4’.

Answer 1

In [111]: lst =  [ ['text',2,3,4], ['text2',4,5,6] ]

In [112]: import operator

In [113]: print(map(operator.add,*lst))
['texttext2', 6, 8, 10]

---

If you don’t know a priori which columns contain text, then you could use a try..except block to handle the text:

lst =  [ ['text',2,3,4], ['text2',4,5,6] ]
result=[]
for column in zip(*lst):
    try:
        result.append(sum(map(int,column)))
    except ValueError:
        pass
print(result)
# [6, 8, 10]