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Home/ Questions/Q 7608189
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T00:51:14+00:00 2026-05-31T00:51:14+00:00

Say my URL is https://foo.bar.com/somedirectory/somefile.php or http://abc.bar.co.uk/somedirectory/somefile.php What would the regex be to get

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Say my URL is

  • https://foo.bar.com/somedirectory/somefile.php or

  • http://abc.bar.co.uk/somedirectory/somefile.php

What would the regex be to get

  • /somedirectory/somefile.php or

  • somedirectory/somefile.php?

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  1. Editorial Team
    Editorial Team
    2026-05-31T00:51:15+00:00Added an answer on May 31, 2026 at 12:51 am

    Assuming that your URL always starts with either http:// or https://, this should work (and since you didn’t specify a language, here’s an implementation in Perl):

    use strict;
    use warnings;
    
    my @urls=("https://foo.bar.com/somedirectory/somefile.php", "http://abc.bar.co.uk/somedirectory/somefile.php");
    
    foreach my $url(@urls)
    {
      if($url=~/^http(?:s)?:\/\/[^\/]+(\/.*)$/)
      {
        print "$1\n";
      }
      else
      {
        print "$url did not match!\n";
      }
    }
    

    The output is:

    /somedirectory/somefile.php
    /somedirectory/somefile.php
    
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