Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8797029
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 13, 20262026-06-13T23:45:42+00:00 2026-06-13T23:45:42+00:00

Say we have strings like: string s1 = a < 5; string s2 =

  • 0

Say we have strings like:

string s1 = "a < 5";
string s2 = "b >= 7";
string s3 = "c <= 8";
...

I want to convert such strings into BinaryExpression objects similar to what we get by using:

  BinaryExpression b1 = Expression.MakeBinary( ExpressionType.LessThan, Expression.Parameter( typeof( int ), "a" ), Expression.Constant( 5, typeof( int ) ) );
  BinaryExpression b2 = Expression.MakeBinary( ExpressionType.GreaterThanOrEqual, Expression.Parameter( typeof( int ), "b" ), Expression.Constant( 7, typeof( int ) ) );
  BinaryExpression b3 = Expression.MakeBinary( ExpressionType.LessThanOrEqual, Expression.Parameter( typeof( int ), "c" ), Expression.Constant( 8, typeof( int ) ) );

I have created the method below:

BinaryExpression ConvertStringToBinaryExpression( string exp )
{
  string[] s = exp.Split( ' ' );
  string param = s[ 0 ];
  string comparison = s[ 1 ];
  int constant = int.Parse( s[ 2 ] );
  if ( comparison == "<" )
    return Expression.MakeBinary( ExpressionType.LessThan, Expression.Parameter( typeof ( int ), param ), Expression.Constant( constant, typeof ( int ) ) );
  else if ( comparison == "<=" )
    return Expression.MakeBinary( ExpressionType.LessThanOrEqual, Expression.Parameter( typeof ( int ), param ), Expression.Constant( constant, typeof ( int ) ) );
  else if ( comparison == ">" )
    return Expression.MakeBinary( ExpressionType.GreaterThan, Expression.Parameter( typeof ( int ), param ), Expression.Constant( constant, typeof ( int ) ) );
  else if ( comparison == ">=" )
    return Expression.MakeBinary( ExpressionType.GreaterThanOrEqual, Expression.Parameter( typeof ( int ), param ), Expression.Constant( constant, typeof ( int ) ) );
  else
    throw new ArgumentException( "Invalid expression.", "exp" );
}

However, the above method does not work properly if, for example, we have strings like:

string s4 = "a< 5"  // no space between 'a' and '<'
string s5 = "b>=9"  // no space at all
string s6 = "c <=7"  // no space betwen '<=' and '7'

What is the easiest way to make it more robust and reliable?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-13T23:45:44+00:00Added an answer on June 13, 2026 at 11:45 pm

    As Harsha pointed it out regex would make your task simple

    Match m=Regex.Match("var4 <= 433",@"(?'leftOperand'\w+)\s*(?'operator'(<|<=|>|>=))\s*(?'rightOperand'\w+)");
    m.Groups["leftOperand"].Value;//the varaible or constant on left side of the operator
    m.Groups["operator"].Value;//the operator
    m.Groups["rightOperand"].Value;//the varaible or constant on right side of the operator
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Let's say I have a string like: $text = <object>item_id1a2b3</object>xxx<object>item_id4c5d6</object> I want to convert
Say if I have a string like this char foo[10] = %r1%r2; I want
Let's say I have strings like this: PH&N 2015 LifeTime Series D PH&N 2020
say I have a string like so Testing How could I have it remove
So say I have a string like so of a path $path = '/path/to/../../up/something.txt';
Let's say I have a string like this: var str = /abcd/efgh/ijkl/xxx-1/xxx-2; How do
Let's say I have a string like this: String test = hfikoebndolahsdHEL123LOkjahhsdqhuihs; And then
Let's say I have two strings like this: XABY XBAY A simple regex that
Let's say I have a string like this. Dim str As String = code
So lets say I have an string like so. $pizza = 1,2,3,5-4,7; and what

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.