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Home/ Questions/Q 6901925
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T07:44:04+00:00 2026-05-27T07:44:04+00:00

Say we want to make a function like minBy that returns all elements of

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Say we want to make a function like minBy that returns all elements of equal minimalism in a collection:

def multiMinBy[A, B: Ordering](xs: Traversable[A])(f: A => B) = {
  val minVal = f(xs minBy f)
  xs filter (f(_) == minVal)
}

scala> multiMinBy(List("zza","zzza","zzb","zzzb"))(_.last)
res33: Traversable[java.lang.String] = List(zza, zzza)

So far, so good, except that we have a Traversable back instead of our initial List.

So I tried changing the signature to

def multiMinBy[A, B: Ordering, C <: Traversable[A]](xs: C)(f: A => B)

in the hope I might get a C back rather than a Traversable[A]. However, I don’t get anything back:

scala> multiMinBy(List("zza","zzza","zzb","zzzb"))(_.last)

<console>:9: error: inferred type arguments [Nothing,Nothing,List[java.lang.String]] 
do not conform to method multiMinBy's type parameter bounds [A,B,C <: Traversable[A]]

I think this is because we have C appearing in the arguments before A has been inferred? So I flipped the order of the arguments, and added a cast:

def multiMinBy[A, B: Ordering, C <: Traversable[A]](f: A => B)(xs: C) = {
  val minVal = f(xs minBy f)
  (xs filter (f(_) == minVal)).asInstanceOf[C]
}

which works, except we have to call it like this:

multiMinBy((x: String) => x.last)(List("zza","zzza","zzb","zzzb"))

Is there a way to retain the original syntax, while getting the right collection type back?

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  1. Editorial Team
    Editorial Team
    2026-05-27T07:44:05+00:00Added an answer on May 27, 2026 at 7:44 am

    I think Miles Sabin solution is way too complex. Scala’s collection already have the necessary machinery to make it work, with a very small change:

    import scala.collection.TraversableLike
    def multiMinBy[A, B: Ordering, C <: Traversable[A]]
                  (xs: C with TraversableLike[A, C])
                  (f: A => B): C = {
      val minVal = f(xs minBy f)
      xs filter (f(_) == minVal)
    }
    
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