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Home/ Questions/Q 6026147
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T04:24:13+00:00 2026-05-23T04:24:13+00:00

Say,I have 5 paragraphs in the page. if I execute: p_array=$(‘p’); second_p=$(‘p:eq(1)’); $.inArray(second_p,p_array); I

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Say,I have 5 paragraphs in the page.

if I execute:

p_array=$('p');
second_p=$('p:eq(1)');
$.inArray(second_p,p_array);

I get -1.
Any explanation?

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  1. Editorial Team
    Editorial Team
    2026-05-23T04:24:13+00:00Added an answer on May 23, 2026 at 4:24 am

    Neither p_array nor second_p are arrays.

    They are jQuery objects.

    More specifically, p_array is a jQuery object containing a set of 5 DOM nodes. second_p is a jQuery object containing a set of 1 DOM node.

    $.inArray can function on these jQuery sets of nodes, but you can’t compare a set against a set.

    If you extract that one DOM node using the array subscript operator (jQueryObj[i]), then you’re no longer comparing a set against a set:

    var p_array=$('p');
    var second_p=$('p:eq(1)');
    alert($.inArray(second_p[0], p_array)); // result: 1
    

    See a live demo here.

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