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Home/ Questions/Q 7069853
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T05:29:46+00:00 2026-05-28T05:29:46+00:00

scala> val s = 7.toBinayString <console>:7: error: value toBinayString is not a member of

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scala> val s = 7.toBinayString 
<console>:7: error: value toBinayString is not a member of Int
       val s = 7.toBinayString 
                 ^

scala> val k = 7
k: Int = 7
scala> k.toBinaryString 
res44: String = 111

Since val k = 7 and 7 are identified as Int, not as RichInt or java.lang.Integer I don’t see why they are handled differently.

Why is there a difference?

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  1. Editorial Team
    Editorial Team
    2026-05-28T05:29:47+00:00Added an answer on May 28, 2026 at 5:29 am

    Because of the spelling mistake.

    toBinayString -> toBinaryString 
    

    enter image description here

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