Question

Scanner s = null;
    try {
        s = new Scanner(new BufferedReader(new FileReader("rates.txt")));
            for (int i=0; i<9; i++){
                while(s.hasNext()){rates[i] = s.next();}
                System.out.println(rates[i]);
            }
    }catch (IOException e){
        System.out.println(e);
    }
    finally {
        if (s != null) {
            s.close();
        }
    }

When I run this code, it reads the last chunk of characters in my txt file, places them in rates[0], sticks null in 1-9. I’m not sure why it’s reading the end of my file first. The contents of the txt are below..

USD 1.34

EUR 1.00

JPY 126.28

GBP 0.88

INR 60.20

It reads the 60.20, which is all it is recording in the array. Any help would be appreciated. I guess I could give you the results of running this code:

run:
60.20
null
null
null
null
null
null
null
null
BUILD SUCCESSFUL (total time: 0 seconds)

Answer 1

while(s.hasNext()){rates[i] = s.next();}

In plain english, this says: While there are tokens left, put the next token into rates[i].

So it will put the first token into rates[i], then the next token into rates[i], then the next token into rates[i], …, and finally the last token into rates[i]. Since i is not modified, all the values are written into the same element of the array, overwriting the previously read values.