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Home/ Questions/Q 8052645
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T07:35:49+00:00 2026-06-05T07:35:49+00:00

Scheme implementation : tinyscheme Here is my try: (with-output-to-file biophilia.c (lambda (output-port) (write Hello

  • 0

Scheme implementation : tinyscheme

Here is my try:

(with-output-to-file "biophilia.c"
  (lambda (output-port)
    (write "Hello" output-port)))

Ceates biophilia.c with following content:

Error: ( : 26) not enough arguments

What am I doing wrong here? how to repair it?

(define (with-output-to-file s p)
     (let ((outport (open-output-file s)))
          (if (eq? outport #f)
               #f
               (let ((prev-outport (current-output-port)))
                    (set-output-port outport)
                    (let ((res (p)))
                         (close-output-port outport)
                         (set-output-port prev-outport)
                         res)))))
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T07:35:53+00:00Added an answer on June 5, 2026 at 7:35 am

    You are calling with-output-to-file incorrectly.

    The second argument is a thunk, and not a procedure expecting a port argument.

    So call it like:

    (with-output-to-file "biophilia.c"
      (lambda ()
        (write "Hello")))
    

    with-output-to-file already does the re-binding of the current-port for you (as you tried in your reconstruction).

    See the Racket docs for it here.

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