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Home/ Questions/Q 8778479
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T19:32:56+00:00 2026-06-13T19:32:56+00:00

<script> $(document).ready(function() { $(‘form[meldaan] input’).keyup(function() { var empty = false; $(‘form[meldaan] input’).each(function() { if

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  <script>
 $(document).ready(function() {
$('form["meldaan"] input').keyup(function() {

    var empty = false;
    $('form["meldaan"] input').each(function() {
        if ($(this).val() == '') {
            empty = true;
        }
    });

    if (empty) {
        $('#register').attr('disabled', 'disabled');
    } else {
        $('#register').removeAttr('disabled');
    }
});
});
</script>

This script works fine with one form, but I have two or three different forms on one page. I want each form to be treated different, if I use this code all fields in ALL forms need to be filled in, which I obviously don’t want.

How can I identify the unique forms? Say one form is named name="formone" and the other name="formtwo". How would I implement that? (It’s okay if I have to make more functions).

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  1. Editorial Team
    Editorial Team
    2026-06-13T19:32:57+00:00Added an answer on June 13, 2026 at 7:32 pm

    You just need to adjust your selector:

    $('form[name="formone"] > input')
    

    Update: @Andre, in your live example inputs are not direct children of the form element, so you need to use:

    $('form[name="formone"] input')
    

    Update 2: if you are using an id:

    $('#formid input')
    
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