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Home/ Questions/Q 530979
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:15:12+00:00 2026-05-13T09:15:12+00:00

<script> function urlencode(str) { return escape(str).replace(‘+’, ‘%2B’).replace(‘%20’, ‘+’).replace(‘*’, ‘%2A’).replace(‘/’, ‘%2F’).replace(‘@’, ‘%40’); } $(‘input#q’).keyup(function(e) {

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<script>
function urlencode(str) {
   return escape(str).replace('+', '%2B').replace('%20', '+').replace('*', '%2A').replace('/', '%2F').replace('@', '%40');
}
$('input#q').keyup(function(e) {
 if(e.keyCode == 13) {
  if($('input#q').val().length > 2) 
  { 
   $('input#q').val() = urlencode($('input#q').val());
   document.search_form.submit();
  }
 }
});
$('input#search').click(function() {
 if($('input#q').val().length > 2) 
 { 
  $('input#q').val() = urlencode($('input#q').val());
  document.search_form.submit();
 } 
});
</script>

when i click the search button i get the following error : “Uncaught ReferenceError: Invalid left-hand side in assignment”
But the code is actually the same as when i press “enter”. Can someone explain?

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:15:12+00:00Added an answer on May 13, 2026 at 9:15 am

    You can’t assign a new value to the result of a function

    $('input#q').val() = urlencode($('input#q').val());
    

    Use this instead:

    $('input#q').val(urlencode($('input#q').val()))
    

    It wouldn’t work with the keypress either – maybe the page is simply submitted after the same js error occurs.

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