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Editorial Team
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Asked: 2026-05-29T04:16:43+00:00

<script type=text/javascript> $.getScript(‘http://connect.facebook.net/sv_SE/all.js#xfbml=1’, function(){ $(‘body’).append(‘<div id=fb-root></div><div class=fb-like data-href=http://www.google.se data-send=false data-layout=button_count data-width=450 data-show-faces=false data-font=verdana></div>’); });

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<script type="text/javascript">
    $.getScript('http://connect.facebook.net/sv_SE/all.js#xfbml=1', function(){
        $('body').append('<div id="fb-root"></div><div class="fb-like" data-href="http://www.google.se" data-send="false" data-layout="button_count" data-width="450" data-show-faces="false" data-font="verdana"></div>');
    });
</script>

No button is showing. Isnt this the correct way to use getScript?

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1 Answer

  1. Editorial Team

    You should load the DIV into the DOM first, then load the script in to parse the DOM objects.

    <script type="text/javascript">
    $('body').append('<div id="fb-root"></div><div class="fb-like" data-href="http://www.google.se" data-send="false" data-layout="button_count" data-width="450" data-show-faces="false" data-font="verdana"></div>');
    $.getScript('http://connect.facebook.net/sv_SE/all.js#xfbml=1', function(){

    });
</script>
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