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Home/ Questions/Q 8979715
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:54:36+00:00 2026-06-15T19:54:36+00:00

<script type=text/javascript> var prev = ”; $(‘#zzz img’).click(function(){ if (prev != ”) $(‘#img_’ +

  • 0
 <script type="text/javascript">
 var prev = '';
 $('#zzz img').click(function(){
 if (prev != '')
  $('#img_' + prev).css('border', '1px solid #eee');

 prev = $(this).attr('id').replace('img_', '');

 $(this).css('border', '1px solid #535666');
 $('#imgid').val(prev);
});
 </script>

css:

ul#zzz {clear: both}
ul#zzz li {display: inline ; padding: 3px}
ul#zzz img {border: 1px solid #eee}

html:

<input type="text" id="imgid" name="imgid" value="">
<ul id="zzz">
<li><img name="1" id="img_1" src="img_1.png"></li>
<li><img name="2" id="img_2" src="img_2.png"></li>
<li><img name="3" id="img_3" src="img_3.png"></li>
</ul>

still cant understnd whats wrong. before everything was fine, nothing has changed. any ideas? thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:54:38+00:00Added an answer on June 15, 2026 at 7:54 pm

    put all in document ready handler and see if helps:

    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
    <script type="text/javascript">
     jQuery(function($){
        var prev = '';
        $('#zzz img').click(function(){
          if (prev != '')
           $('#img_' + prev).css('border', '1px solid #eee');
    
           prev = $(this).attr('id').replace('img_', '');
    
           $(this).css('border', '1px solid #535666');
           $('#imgid').val(prev);
        });
       });
    </script>
    

    Hoping that you are having jQuery plugin loaded before this script.

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