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Home/ Questions/Q 8506249
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T02:32:31+00:00 2026-06-11T02:32:31+00:00

<script> var text = a’s ..a’s …\… ; text = convert(text); function convert( text

  • 0
<script>
var text = "a's ..a's ...\"... ";
text = convert(text);
function convert( text )
{
    var n = text.replace(/\'/g, "&#039;");
    n = text.replace(/\"/g,"&quot;");
    return n;

}
console.log(text);
document.write(text);

</script>

The problem is that when it replace the second time it take doesnt “remember” what it replaced the first time, so only the last replace is returned.

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  1. Editorial Team
    Editorial Team
    2026-06-11T02:32:32+00:00Added an answer on June 11, 2026 at 2:32 am

    That’s because you are replacing the original text string in the second replace, instead of n, which is the value of the replaced text:

    function convert( text )
    {
        var n = text.replace(/\'/g, "&#039;");
        n = n.replace(/\"/g,"&quot;");
        return n;
    }
    

    replace does not modify your original string. Instead, it returns a new modified string . You can also do both replaces in a single statement:

    return text.replace(/\'/g, "&#039;").replace(/\"/g,"&quot;");
    
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