Question

see i have below code

#include<stdio.h>
int main ( int argc, char *argv[] )
{
        int i=0;
        for(i=1;i<argc-1;i++)
          printf(" %s \n",argv[i]);
        return 0;
}

compiles and run as follows

gcc test.c
./a.out 1 * 2

and now its o/p is scarred..!

o/p is :

 1 
 a.out 
 Desktop 
 Documents 
 Downloads 
 ipmsg.log 
 linux-fusion-3.2.6 
 Music 
 Pictures 
 Public 
 Templates 
 test.c 

Answer 1

You could invoke your test using

./a.out 1 \* 2

if you want to pass * as an argument. You can also use single quotes '*' (as suggested by Esa) or double quotes "*".

Note also that your loop currently ignores the last argument. Use i<argc as your exit condition if this isn’t deliberate.