Question

see i have one code like this

int main () {
    uint32_t i ;
    for(i=4;i>=0;i--)
            printf("i is %d \n",i);

    return 0;
}

it goes in infinite loop.
why i’s value goes below 0 & still loop is going to executive?

Answer 1

uint32_t means unsigned integer and so its value is always >= 0 – thus your loop executes infinitely.

Note that many compilers will issue a warning indicating that i>=0 comparison is always true.